Nexting a For from an IF...THEN

[ardentcrest]

Me again

Code:

2004 for xx=length to 1 step -1
2006    if z$(xx)=" " then next xx

Syntax Error. Unexpected token 'NEXT' <NEXT>



Why are the hard thing easy, and what should be easy hard

[boriel]

Me again

Code:

2004 for xx=length to 1 step -1
2006    if z$(xx)=" " then next xx

Syntax Error. Unexpected token 'NEXT' <NEXT>



Why are the hard thing easy, and what should be easy hard

I've splitted this topic and moved this question into here, since it's more generic to ZX BASIC syntax. Please, post your questions separated, if possible (one in each thread), so other users might find them more useful.

You can no longer NEXT a for from any point. Instead use CONTINUE FOR to next, or use EXIT FOR to stop the loop:

Code:

2004 for xx=length to 1 step -1
2006    if z$(xx)=" " then CONTINUE FOR: end if
2010 next xx

Read: <!-- m --><a class="postlink" href="http://www.boriel.com/wiki/en/index.php/ZX_BASIC:CONTINUE">http://www.boriel.com/wiki/en/index.php ... C:CONTINUE</a><!-- m -->

[ardentcrest]

I've splitted this topic and moved this question into here, since it's more generic to ZX BASIC syntax. Please, post your questions separated, if possible (one in each thread), so other users might find them more useful.

Good Idea.

Get ready for 2 or 3 new threads a day from me. :mrgreen: :mrgreen: