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+---- Thread: Nexting a For from an IF...THEN (/showthread.php?tid=640)
Nexting a For from an IF...THEN - ardentcrest - 2015-02-17
Me again
Code:
2004 for xx=length to 1 step -1
2006 if z$(xx)=" " then next xxSyntax Error. Unexpected token 'NEXT' <NEXT>
Why are the hard thing easy, and what should be easy hard
Re: Nexting a For from an IF...THEN - boriel - 2015-02-17
ardentcrest Wrote:Me againI've splitted this topic and moved this question into here, since it's more generic to ZX BASIC syntax. Please, post your questions separated, if possible (one in each thread), so other users might find them more useful.
Code:2004 for xx=length to 1 step -1
2006 if z$(xx)=" " then next xx
Syntax Error. Unexpected token 'NEXT' <NEXT>
Why are the hard thing easy, and what should be easy hard
You can no longer NEXT a for from any point. Instead use CONTINUE FOR to next, or use EXIT FOR to stop the loop:
Code:
2004 for xx=length to 1 step -1
2006 if z$(xx)=" " then CONTINUE FOR: end if
2010 next xxRead: <!-- m --><a class="postlink" href="http://www.boriel.com/wiki/en/index.php/ZX_BASIC:CONTINUE">http://www.boriel.com/wiki/en/index.php ... C:CONTINUE</a><!-- m -->
Re: Nexting a For from an IF...THEN - ardentcrest - 2015-02-17
boriel Wrote:I've splitted this topic and moved this question into here, since it's more generic to ZX BASIC syntax. Please, post your questions separated, if possible (one in each thread), so other users might find them more useful.
Good Idea.
Get ready for 2 or 3 new threads a day from me. :mrgreen: :mrgreen: